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標題: 油庫設計熱力計算完整程序 [打印本頁]

作者: yifang 時間: 2012-9-12 19:13
標題: 油庫設計熱力計算完整程序
油庫設計熱力計算完整程序

#define Tqi             13.3
#define Ttu             3.4
#define D                23.76
#define H                12.53
#define PI             3.14159
#define P                800
#define fn             6
#define v                4.5
#define i                0.1
#define N                5
#define Tys             55.0
#define Tyz             70.0
#define Kding          0.35
#define Kdi             0.12
#define Fding          460.1
#define Fbi             935.3
#define Fdi             433
#define nd_80          35
#define md_20          897
#define u                0.0581
#include  <stdio.h>
#include  <math.h>

float R0(float MPa)
{  if(MPa>0.5)
   return (0.00086);
   else if(MPa<0.2)
      return (0.0026);
      else  return (0.0017);
}

double Insert(double x1,double x2,double y1,double y2,double x)
{
return  (y1+(y2-y1)/(x2-x1)*(x-x1));

}

float Md(float t)
  {    return (md_20-(1.825-0.001315*md_20)*(t-20));

}

float Br(float t)
{ int j;
float t1,t2,C1,C2;
float C[12]={1.696,1.729,1.758,1.792,1.825,1.859,
      1.888,1.921,1.955,1.985,2.018,2.047};

   for(j=0;j<=11;j++)
      { if(j*10.0<=t&&(j+1)*10.0>=t)
{ t1=j*10.0; t2=(j+1)*10.0;
   C1=C[j];    C2=C[j+1];
   break;
}
      }

return (Insert(t1,t2,C1,C2,t));

}

float Pz(float md)
{ int k;
float B[30]={1.151,1.130,1.108,0.997,0.974,0.953,
      0.931,0.910,0.888,0.866,0.845,0.824,
      0.803,0.782,0.760,0.739,0.718,0.696,
      0.674,0.653,0.632,0.612,0.592,0.572,
      0.553,0.534,0.516,0.497,0.479,0.462};
float md1,md2,B1,B2;
      for(k=0;k<=29;k++)
      { if(md>=k/100.0+0.73&&md<=(k+1)/100.0+0.73)
{    md1=k/100.0+0.73;       md2=(k+1)/100.0+0.73;

B1=B[k];                   B2=B[k+1];
break;
}

      }
return (Insert(md1,md2,B1,B2,md));
}

float Fr( float Gr, float Pr, float A, float d)
  { float e,n,a2,Td;
if(Gr*Pr>2.0e7)
   {e=0.135;    n=1.0/3;}
   else if(Gr*Pr>=500&&Gr*Pr<=2.0e7)
{e=0.54;    n=1.0/4;}
      else {e=1.18; n=1.0/8;}
a2=e*A/d*pow((Gr*Pr),n);
return a2;
}
float BI_wen(float Tz,float Ty,float MPa,float d)
{    float Td,Tb,md_Td,c,A,B;
      float Gr,Pr,a2,K0; double nd_Td;

Tb=Tz-5;
do
   {Tb-=0.01;
   Td=(Tb+Ty)/2;
   nd_Td=nd_80*(1.0e-6)*exp((-u)*(Td-80));
   md_Td=Md(Td);
   c=Br(Td);
   A=117.5/Md(15.0)*(1-0.00054*Td);
   B=Pz(md_Td/1000);
   Gr=9.81*B*1.0e-3*(Tb-Ty)*d*d*d/(nd_Td*nd_Td);
   Pr=(nd_Td*c*1.0e3*md_Td)/A;
   a2=Fr(Gr,Pr,A,d);
   K0=1/((1/a2)+R0(MPa));

   }
      while(fabs(Ty+K0/a2*(Tz-Ty)-Tb)>0.01);
  printf("\n\t |%5.2f +(%5.2f/%5.2f)*(%5.2f-%5.2f)-%5.2f|=|%f|<=0.01",Ty,K0,a2,Tz,Ty,Tb,(Ty+K0/a2*(Tz-Ty)-Tb));
   printf("\n\t Tb=%5.2f,       K0=%5.1f.",Tb,K0);
   return  K0;

}

void main()
{ float  Hbao,Ty,Dr,a,S,Kbi,K,Tj,md,c,Tz,MPa,d,K0,F,L;
   double Q1,Q2,Q3,Q;
   printf("\n\t Input the value of Tz,MPa and d:\t");
   scanf("%f%f%f",&Tz,&MPa,&d);
   a=10+6*sqrt(v);
   Tj=((4*H/D+1)*Tqi+Ttu)/(4*H/D+2);
{ if((Tyz-Tj)/(Tys-Tj)<2)
         Ty=(Tys+Tyz)/2.0;
   else  Ty=Tj+(Tyz-Tys)/(log((Tyz-Tj)/(Tys-Tj)));
   }
   S=i*pow((1+i),N)/(pow((1+i),N)-1);
   Dr=0.032+0.00013*Ty;
   Hbao=sqrt(fn*Dr*3.6/4.187*8400*(Tys-Tqi)/(P*S))-Dr*3.6/(a*4.187);

   printf("\n\t Hbao=%4.2fmm.",Hbao);

   Kbi=Dr*1000/Hbao;
   K=(Kding*(Fding+0.1*Fbi)+Kbi*0.9*Fbi+Kdi*Fdi)/(Fding+Fbi+Fdi);
   md=Md(Ty);          c=Br(Ty);
   Q1=PI*D*D/4*0.9*H*md*c*(Tyz-Tys);
   Q2=6*12.5/100*PI*D*D/4*0.9*H*md;
   Q3=K*(Fding+Fbi+Fdi)*(Ty-Tj);
   Q=(Q1+Q2)/(3.6*48)+Q3;
   K0=BI_wen(Tz,Ty,MPa,d);

   printf("\n\t Q1=%7.0fkJ, Q2=%7.0fkJ.\n\t Q3=%7.0fW,    Q=%7.0fW.",Q1,Q2,Q3,Q);

   F=1.1*Q/(K0*(Tz-Ty));             L=F/(PI*d);

   printf("\n\t F =%5.1fm2,       L=%6.1fm.",F,L);

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